2007-12-16 10:16:42 · 0 answers · asked by Anonymous in Science & Mathematics ➔ Astronomy & Space
It varies by many thousands of miles. But it is an average of about 240,000 miles, and at 5,280 feet per mile that is 1,267,200,000 feet.
2007-12-16 10:20:15 · answer #1 · answered by campbelp2002 7 · 0⤊ 0⤋
For the best answers, search on this site https://shorturl.im/avpzS
Ignoring the impossibility of the Moon staying 1000 feet away. Actually, the average acceleration would be about the same. On one side of the Earth the acceleration would be lessened due to the Moon, but on the other side of the Earth, the force of the Moon would add to the gravitational pull. Gravity and tidal forces are not impeded by the presence of the Earth in between. That is, at some point, a an object is between the Earth and the Moon, 1000 feet away, and gravity would feel lessened. An object on the other side of the Earth would have both the Earth and the Moon beneath them, and gravity would feel increased. .
2016-04-05 05:34:57 · answer #2 · answered by Janet 4 · 0⤊ 0⤋
First of all, it would take some magic to hold the moon up that close. But if it could be done, then the Earth would pull down with 1 g, and the moon would pull up with 0.1654 g. So the net effect would be 0.8345 g's.
2016-03-19 03:46:54 · answer #3 · answered by Anonymous · 0⤊ 0⤋
The average centre-to-centre distance from the Earth to the Moon is 384,403 km, which is about thirty times the diameter of the Earth.
2007-12-16 10:38:29 · answer #4 · answered by Anonymous · 0⤊ 0⤋
about 1,300,000 feet.
2007-12-16 10:29:12 · answer #5 · answered by ChrisCT 4 · 0⤊ 0⤋