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Lim as n goes to infinity ( n +1)/(n*sqrt(n)) using sqz. them. please help.

2007-12-16 09:52:56 · 1 answers · asked by ramblingon4u 1 in Science & Mathematics Mathematics

1 answers

It equals (1 + 1/n)/sqrt(n).

So it's bounded by 2/sqrt(n).

And that of course goes to 0. :)

2007-12-16 11:36:31 · answer #1 · answered by Curt Monash 7 · 0 0

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