Can someone please help me with this calculus problem?

Question

If f(x)=2/(x-3), find f'(4)________.


Use this to find the equation of the tangent line to the curve y=2/(x-3) at the point (4,2). The equation of this tangent line can be written in the form y=mx+b where m is:______
and where b is:________

Answer 1

using the quotient rule:

-2
_____ = f'[x]... set x= 4
(x-3)^2

-2/(1)^2 = -2 = m

y=mx+b
2=(-2)(4)+b
2=-8+b
b= 10

m=-2
b=10