2007-12-16 09:50:46 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
multiply everything by 4
y-2 + 2y = 40
-2 + 3y = 40
3y = 42
y= 14
2007-12-16 09:54:31 · answer #1 · answered by ¿ /\/ 馬 ? 7 · 0⤊ 0⤋
multiply y/2 by 2, giving 2y/4, then add, giving 2y+y-2/4 = 10.
this goes to 3y-2/4 = 10
then multiply by 4 on both sides: 3y-2 = 40
then add 2 to each side: 3y = 42
finally, divide by 3: y = 14
check:
14-2/4 + 14/2 = 10
12/4 + 7 = 10
3 + 7 = 10
10 = 10
2007-12-16 17:57:14 · answer #2 · answered by phifreak1618 2 · 0⤊ 0⤋
(y - 2)/4 + y/2 = 10
LCD = 4, multiply both sides by 4 to clear the fractions
y - 2 + 2y - 40
3y = 42
y = 14
2007-12-16 17:54:52 · answer #3 · answered by kindricko 7 · 0⤊ 0⤋
(y-2)/4+y/2 = 10
(y-2)/4+2y/4 = 10
(3y-2)/4 = 10
3y - 2 = 40
3y = 42
y = 14
2007-12-16 17:56:48 · answer #4 · answered by DWRead 7 · 0⤊ 0⤋
it is a number between 16 and 17.
2007-12-16 17:59:31 · answer #5 · answered by Tri T 1 · 0⤊ 1⤋