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What is the first and second derivatives of f(x)= x/(x-1)^2?

I'm confused...do u have to use the chain rule?

2007-12-16 08:49:34 · 1 answers · asked by Asiana 1 in Science & Mathematics Mathematics

1 answers

take f[x] = x and g[x] = (x-1)^2

Quotient rule states that f'[x]g[x] - f[x]g'[x]/ (g[x])^2
f[x]= x
f'[x]= 1
g[x]= (x-1)^2
g'[x]= 2(x-1) <-- using the chain rule

Plug in those values to get the first derivative and do the same with the 2nd derivative.

2007-12-16 08:58:24 · answer #1 · answered by ¿ /\/ 馬 ? 7 · 0 0

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