the solubility of AgBrOsub3 in water is 0.0072g/L. calculate ksp.?

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2007-12-16 08:43:54 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry

Divide g/L by formula mass to get solubility in moles/L; call it Y

Then use definition of Ksp

In this case, Ksp = [Ag+] x [BrO3-] = Y x Y

2007-12-16 09:00:35 · answer #1 · answered by Facts Matter 7 · 1⤊ 0⤋

KSP= {Ag}{Br}{O}
0.0072 X 0.0072 X 0.0072
= 3.43 X 10-7

2007-12-16 09:06:37 · answer #2 · answered by Storm 2 · 0⤊ 0⤋