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2007-12-16 08:23:09 · 1 answers · asked by kim L 1 in Science & Mathematics Mathematics

1 answers

Let p(x) = x³ -6x² + 11x -6.
Since 3 is a zero, x+ 3 is a factor.
Next p(x)/(x-3) = x² - 3x + 2 = (x-1)(x-2)
So the zeros of p(x) are 1, 2 and 3.

2007-12-16 09:08:29 · answer #1 · answered by steiner1745 7 · 0 0

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