Can someone explain me how to graph the inverse of a function on a TI-83 plus. example x = y + 2, I know the inverse is y = x - 2. I am using my TI-83 plus, how can I graph the inverse of y = x^2, I know that on my TI-83 on
Y1 = X^2
Y2 = ? I just need to know what to input on Y2, thanks for anyones help
2007-12-16 08:15:18 · 4 answers · asked by Batman 1 in Science & Mathematics ➔ Mathematics
The inverse of y = x^2 is y = sqrt(x).
2007-12-16 08:19:18 · answer #1 · answered by DavidK93 7 · 0⤊ 0⤋
The inverse of x^2 is
+/- sqrt(x)
so to truly get the inverse you actually need to input two functions
Y2: sqrt(x)
Y3: -sqrt(x)
2007-12-16 08:23:14 · answer #2 · answered by b1gmuff 3 · 0⤊ 0⤋
x^1/2 ???...just guessing
2007-12-16 08:18:58 · answer #3 · answered by Anonymous · 0⤊ 0⤋
-X^2
i think??
2007-12-16 08:18:59 · answer #4 · answered by Music=Life 2 · 0⤊ 0⤋