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3 answers

Let M be your matrix.

det M = 4 * 1 - 2 * 3 = 4 - 1 = 3

M^(-1) = (det M)^(-1) M_c^T

where M_c is the cofactor matrix and M_c^T is its transpose. which is |1 -3| |-2 4| = |1 2| |3 4|.

Now, det M ^(-1) = 3^(-1) = 2 in Z_5

So the matrix inverse is

| 2 4 |
| 1 3 |

2007-12-16 08:06:18 · answer #1 · answered by jaz_will 5 · 0 0

4 3
2 1
In the following all calculations are done modulo 5.
The determinant of the matrix in Z_5 is 4 - 6 = 3
So the inverse is
1/3* 1 -3
.......-2 4

= 2* 1 2
........3 4
= 2 4
...1 3

Check:
In Z_5
4 3 times.... 2 4
2 1 ............ 1 3
equals
1 0
0 1.

2007-12-16 08:08:59 · answer #2 · answered by steiner1745 7 · 0 0

The rule for inverting a 2x2 matrix: [a b] [c d] is 1 / (ad-bc) times [d -b] [-c a]

2016-04-09 07:30:34 · answer #3 · answered by ? 4 · 0 0

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