Find the vaule of k so that (k+2)x- 3y= 1 has slope 2?

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Find the vaule of k so that (k+2)x- 3y= 1 has slope 2?

2007-12-16 07:20:29 · 2 answers · asked by Hardeo R 1 in Science & Mathematics ➔ Mathematics

2 answers

3y = (k + 2) x - 1
y = [ (k + 2) / 3 ] x - 1 / 3
(k + 2) / 3 = 2
k + 2 = 6
k = 4

2007-12-20 05:31:11 · answer #1 · answered by Como 7 · 1⤊ 0⤋

Rewrite the equation in slope-intercept form, i.e., y = mx + b, where m is the slope and b is the y-intercept.

(k+2)x- 3y= 1
-3y = -(k+2)x + 1
y = ((k+2)/3)x - 1/3

slope = 2
(k+2)/3 = 2
(k+2) = 6
k = 4, making the equation
y = 2x - 1/3

2007-12-16 15:28:31 · answer #2 · answered by DWRead 7 · 0⤊ 0⤋