Solve for x?

Question

ln(x)- ln(x+1)=1
please help. How do I do this and what should I get as my answer.

Answer 1

ln [ (x) / (x + 1) ] = 1
x / (x + 1) = e^1
x = e (x + 1)
x = e x + e
(e - 1) x = - e
x = - e / (e - 1)
x = e / (1 - e)

Answer 2

x Is 1 so 1-1+1=1

Answer 3

Re-Edit- ln (x) - ln (x+1)=1
so then ln {x/(x+1)}=1

ln is in base 10, so that means that since log (10) equals one, then x/(x+1)=10, then
x= 10x+10, then
-9x=10, then
x= -10/9 then
that means log{(-10/9)/(-1/9) or log (10)=1.
http://www.sosmath.com/algebra/logs/log4/log44/log442/log442.html

Sorry about that ...it got me very confused..

Answer 4

x = 0

Answer 5

its really simple.
subtract the 1 next to the plus sign from the 1 next to the equal sign.
x=0
to check your answer plug 0 (or your answer) into x
(0+1)=1.

Answer 6

x=0
o+1=1

Answer 7

I think it is impossible.

ln(x)-ln(x+1) = ln(x/(x+1))

so

ln[x/(x+1)] = 1


e = x/(x+1)

x = -e/(e-1)

x cannot be negative, because its not in the domain for ln(x).

no solution

Answer 8

If a and b are two numbers, ln(a)-ln(b)=ln(a/b)
ln(x)-ln(x+1)=ln(x/(x+1))=1
x/(x+1)=e (by definition of logs)
x=(x+1)e
x=xe+e
x-xe=e
x(1-e)=e
x=e/(1-e)

Answer 9

In(x)-In(x+1)=1
Inx-Inx+1=1
-1 -1

x=0

sorry, bub
pretty sure it's right?

Answer 10

Use a scientific calculator that shud be easy...