Distance between coordinate points (2/3, 1/6) and (4/7, 3/11)?

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Distance between coordinate points (2/3, 1/6) and (4/7, 3/11)?

2007-12-16 07:09:06 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

2 answers

d² = (4/7 - 2/3)² + (3/11 - 1/6)²
d² = (12/21 - 14/21)² + (18/66 - 11/66)²
d² = 4 / 21² + 49 / 66²
d² = 4 / 441 + 49 / 4356
d² = [ (4)(4356) + (49)(441) / (441)(4356) ]
d = 0.142

2007-12-20 04:05:57 · answer #1 · answered by Como 7 · 2⤊ 0⤋

use the distance formula
d=sqrt{(x2-x1)^2+(y2-y1)^2}
d= sqrt{(4/7-2/3)^2+(3/11-1/6)^2}
d= 0.1425

2007-12-16 07:18:01 · answer #2 · answered by Rector 2 · 0⤊ 0⤋