3*5i(3i+4*5i)=3*5i*3i+3.5i*4*5i
=3*15i^2+12*25i*
=-45-300
=-345
3i/5
2007-12-16 06:38:43
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answer #1
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answered by Rector 2
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Algebra is simply the logical mathematical means of finding an unknown.
More simply put. A step by step approach of finding the number you are missing.
If there are sellings eggs for $1.23 a dozen. Algebra is the way of finding out how much each egg is worth.
x=1 egg 12x=1.23 now you simplify using algebra to get your answer.
2007-12-16 06:42:48
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answer #2
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answered by Sgiandubh 1
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3 square root of 15 + 60.
2007-12-16 06:33:16
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answer #3
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answered by james brown 4
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For a million my maximum suitable wager is ((a million/x)-(a million/y))/(a million+y/x). So the 1st area i might pass away on my own yet on the ((x+y)/x) you divide the x and you finally end up with: ((a million/x)-(a million/y))/(x/x+y), a selection divided by potential of a selection is one so x/x will equivalent a million so for this reason: ((a million/x)-(a million/y))/(a million+y/x) And for selection 2 it pisses me off too plenty stuff happening lol.
2016-11-27 21:29:40
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answer #4
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answered by ? 4
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Here's the problem: both problems involve multiplying or dividing by the squareroot of a negative number. So both problems are NO SOLUTION.
I hope this helped!
Have a Merry Christmas!
2007-12-16 06:36:49
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answer #5
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answered by Anonymous
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-3 root 15 -60
then
i rad 3
over
5
imaginary numbers
2007-12-16 06:38:25
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answer #6
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answered by D 2
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Can't square root negative numbers.
2007-12-16 06:33:10
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answer #7
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answered by ¿ /\/ 馬 ? 7
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1.) 3sqrt(-5) * [sqrt(-3) + 4sqrt(-5)]
3sqrt(-5) * sqrt(-3) + 3sqrt(-5) * 4sqrt(-5)
3sqrt(15) + 12sqrt(25)
3sqrt(15) + 12*5
3(sqrt(15) + 20)
2.) sqrt(-3)/sqrt(25)
sqrt(-3)/5
(sqrt(3)*i)/5
2007-12-16 06:40:39
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answer #8
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answered by Anonymous
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u cant square root a negative -_-
no solution
2007-12-16 06:39:18
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answer #9
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answered by albert l 2
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