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2007-12-16 06:29:20 · 9 answers · asked by Anonymous in Science & Mathematics Mathematics

9 answers

3*5i(3i+4*5i)=3*5i*3i+3.5i*4*5i
=3*15i^2+12*25i*
=-45-300
=-345

3i/5

2007-12-16 06:38:43 · answer #1 · answered by Rector 2 · 0 0

Algebra is simply the logical mathematical means of finding an unknown.
More simply put. A step by step approach of finding the number you are missing.
If there are sellings eggs for $1.23 a dozen. Algebra is the way of finding out how much each egg is worth.
x=1 egg 12x=1.23 now you simplify using algebra to get your answer.

2007-12-16 06:42:48 · answer #2 · answered by Sgiandubh 1 · 0 0

3 square root of 15 + 60.

2007-12-16 06:33:16 · answer #3 · answered by james brown 4 · 0 1

For a million my maximum suitable wager is ((a million/x)-(a million/y))/(a million+y/x). So the 1st area i might pass away on my own yet on the ((x+y)/x) you divide the x and you finally end up with: ((a million/x)-(a million/y))/(x/x+y), a selection divided by potential of a selection is one so x/x will equivalent a million so for this reason: ((a million/x)-(a million/y))/(a million+y/x) And for selection 2 it pisses me off too plenty stuff happening lol.

2016-11-27 21:29:40 · answer #4 · answered by ? 4 · 0 0

Here's the problem: both problems involve multiplying or dividing by the squareroot of a negative number. So both problems are NO SOLUTION.

I hope this helped!

Have a Merry Christmas!

2007-12-16 06:36:49 · answer #5 · answered by Anonymous · 0 2

-3 root 15 -60

then
i rad 3
over
5

imaginary numbers

2007-12-16 06:38:25 · answer #6 · answered by D 2 · 0 1

Can't square root negative numbers.

2007-12-16 06:33:10 · answer #7 · answered by ¿ /\/ 馬 ? 7 · 0 2

1.) 3sqrt(-5) * [sqrt(-3) + 4sqrt(-5)]

3sqrt(-5) * sqrt(-3) + 3sqrt(-5) * 4sqrt(-5)
3sqrt(15) + 12sqrt(25)
3sqrt(15) + 12*5
3(sqrt(15) + 20)


2.) sqrt(-3)/sqrt(25)

sqrt(-3)/5
(sqrt(3)*i)/5

2007-12-16 06:40:39 · answer #8 · answered by Anonymous · 0 0

u cant square root a negative -_-
no solution

2007-12-16 06:39:18 · answer #9 · answered by albert l 2 · 0 2

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