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A roller coaster, (h1 = 30 m, h2 = 15 m, h3 = 25 m), is pulled up to point A where it and its screaming occupants are released from rest. Assuming no friction, calculate the speed at points B, C and D. h1= A is 30m above B. h2= B is 15m below D. h3= B is 25m below C. Help would be greatly appreciated. Thank you. If you have any questions on the view of the diagram please ask.

2007-12-16 05:58:43 · 2 answers · asked by ND03 1 in Science & Mathematics Physics

http://img148.imageshack.us/img148/6906/pfq0002copyst1.gif

the diagram of the roller coaster looks like this except the height of D is 15.

2007-12-16 06:13:33 · update #1

2 answers

Without friction,
Va = 0+
Vb ≈ √(2)(9.80665)(30) ≈ 24 m/s
Vc ≈ √(2)(9.80665)(5) ≈ 9.9 m/s
Vd ≈ √(2)(9.80665)(15) ≈ 17 m/s

2007-12-16 07:03:35 · answer #1 · answered by Helmut 7 · 3 1

All the speeds can be computed from the formula
V = √(2gh) where h is the height below A

Plug 'n chug....

2007-12-16 06:27:32 · answer #2 · answered by Steve 7 · 3 0

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