4q(3p^2-5q)(3p^2+5q)
The numbers after the "^" are powers.
I got the answer 36qp^3-100q^3
2007-12-16 05:12:00 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Nevermind I redid the problem and I think the answer is 36pq^3-100q^3.
2007-12-16 05:15:31 · update #1
Close. Unless I'm really rusty on algebra, it seems like your exponent on "p" is off by one. You multiply "p" squared times "p" squared. So you have p^(2+2) = p^4.
The correct answer would then be
36qp^4 - 100q^3
2007-12-16 05:19:52 · answer #1 · answered by Anonymous · 2⤊ 1⤋
You're almost correct.
4q(3p^2-5q)(3p^2+5q)
= 4q(9p^4 - 25q^2)
= 36qp^4 - 100q^3
2007-12-16 13:21:33 · answer #2 · answered by mathgoddess83209 3 · 0⤊ 0⤋
Execute FOIL upon the latter of the problem then mutilply by 4q... to obtain answer of (36qp^4-100q^3).
2007-12-16 13:30:01 · answer #3 · answered by Manny Angel 2 · 0⤊ 0⤋
4q(3p^2 - 5q)(3p^2 + 5q)
=>4q(9p^4 - 25q^2) = 36p^4q - 100q^3
2007-12-16 13:20:09 · answer #4 · answered by mohanrao d 7 · 1⤊ 0⤋
4q/(9p^4-25q^2)
Just multiply both numerator and denominator by 3p^2 -5q and then simplify.
2007-12-16 13:18:17 · answer #5 · answered by ironduke8159 7 · 0⤊ 1⤋