Find the slope of any line perpendicular to the line through points (6, 3) and (7, 7).
2007-12-16 04:47:55 · 7 answers · asked by mrsstrick27 2 in Science & Mathematics ➔ Mathematics
m1 = (7 - 3) / (7 - 6)
m1 = 4 / 1 = 4
m2 = - 1 / 4 (slope of perpendicular)
Note
m1 x m2 = - 1
2007-12-20 00:14:48 · answer #1 · answered by Como 7 · 1⤊ 0⤋
Slope of line through (6, 3) and (7, 7) is
(7 - 3) / (7 - 6) = 4
Hence, slope of a perpendicular line is negative inverse of 4
= - 1/4
2007-12-16 04:50:54 · answer #2 · answered by Madhukar 7 · 0⤊ 0⤋
what's the slope of the line that passes via those factors? (y2 - y1) / (x2 - x1) = (7 - 3) / (7 - 6) = 4 / a million = 4 A perpendicular line has a slope it quite is the unfavorable reciprocal of the unique line - for this reason, the slope of the perpendicular line is -a million/4
2016-11-27 21:10:57 · answer #3 · answered by ? 4 · 0⤊ 0⤋
the slope of (6,3) and (7,7) is 4
7-3/7-6 = 4
The perpendicular is the inverse so the slope is 1/4
2007-12-16 04:51:57 · answer #4 · answered by ashooter 3 · 0⤊ 0⤋
slope(m) = delta of y / delta of x...
m = change in y / change in x
m = y(subscript)2 - y(sub)1 / x(sub)2 - x(sub)1
(6,3)...x,y sub1.....(7,7)...as x,y sub2
m = (7 - 3) / (7 - 6)
m = 4 / 1
m = 4
2007-12-16 04:57:17 · answer #5 · answered by hmmm 2 · 0⤊ 0⤋
-[(7 - 6)/(7 - 3)]
2007-12-16 04:52:03 · answer #6 · answered by Mark 6 · 0⤊ 0⤋
6=x1
3=y1
7=x 2
7=y2
y2-y1 over x2-x1
2007-12-16 04:52:47 · answer #7 · answered by korean_freak_ruii 3 · 0⤊ 0⤋