intensity of noise problem --> 77=10log(sub 10) (s/10^-12)?

Question

I need to know the steps involved in doing this problem please. This is what i have, tell me if its right and what comes next.
77=10log(sub 10) (s/10^-12)
7.7=log(sub10) (s/10^-12)
10^7.7=S/10^-12
10^7.7 * 10^-12=S


I know the answer is 5.01 * 10^-5 but i dont know how to get there.

Thanks!!!

Answer 1

properties of exponents
10^7.7 * 10^-12
= 10^7 * 10^0.7 * 10^-12
= 10^0.7 * 10^(7 - 12)
= 5.01 * 10^-5

Answer 2

s= 10^7.7 * 10^-12
s = 10^- 4.3
s = 10^.7 * 10^-5
s = 5.01 *10^-5