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30(10-5)-4(12-5)
_______________

10 I2-6I -2(5+2)

the I I means absoute value.

2007-12-16 04:12:42 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

150 - 28
----------------
40 - 14

122
------
26

61
---
13

2007-12-16 05:21:28 · answer #1 · answered by Como 7 · 3 1

30(10 – 5) – 4(12 – 5) / 10 I2– 6I – 2(5+2)
= 30 × 5 – 4 × 7 / 10 × 4 – 2 × 7
= 150 – 28 / 40 – 14
= 122 / 26 = 61/13

2007-12-16 12:22:38 · answer #2 · answered by Pranil 7 · 1 2

[30(5)-4(7)]/[10*4 -2(7)]
= (150-28)/(40 -14) = 122/26 = 61/13 = 4 9/13

2007-12-16 12:20:06 · answer #3 · answered by ironduke8159 7 · 3 0

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