How much water should be aded to obtain a solution that is 60% antifreeze?
.6x-.6=40
.6x=1
x=1/6?
2007-12-16 02:51:42 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
about a quart. 8-)
You are missing any information about volume. You obviously want 40% water and 60% antifreeze, but how much do you have, or how much are you trying to make?
If you have "a" amount of antifreeze, and you want to know "w", how much water to add:
a = .60 (w+a)
10a = 6w + 6a
4a = 6w
w = 4a/6 = 2/3 a
So add 2/3 as much water as you have antifreeze.
2007-12-16 03:17:59 · answer #1 · answered by Computer Guy 7 · 0⤊ 0⤋
u did it wrong
.6x-.6=40
.6x=39.4
x= 65.666...
i used my ti calculator
im right
2007-12-16 02:57:36 · answer #2 · answered by bobble head 3 · 1⤊ 0⤋
i think 40%
2007-12-16 02:58:22 · answer #3 · answered by lalau 3 · 0⤊ 0⤋
Very little
2007-12-16 02:54:50 · answer #4 · answered by eugene65ca 6 · 0⤊ 2⤋