A coin placed 30.0cm from the center ofa rotatating turntable slips when its speed is50.5cm/swhat force causes the centripetal acceleration when the coin is stationary relative to the turntable?what is the coeffecient of static friction
2007-12-16 02:38:17 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Physics
The force required to hold a mass m in circular motion with radius r and velocity v is
F = m v² / r
The only force available to provide this is friction
F = μ m g
where μ is the coefficient of static friction.
Put 'em together:
m v² / r = μ m g
v² / r g = μ
You know the velocity, the radius, and the local acceleration of gravity; plug 'em in and solve for the coefficient of static friction μ.
2007-12-16 02:45:30 · answer #1 · answered by jgoulden 7 · 0⤊ 0⤋
Force causes to move in a circle is the friction force
Friction = mV²/r
µ(mg)=mV²/r
µ(9.8)=(0.505)²/(0.3)
µ=0.08674319728
coeffecient of static friction = 0.08674319728
2007-12-16 02:46:05 · answer #2 · answered by Murtaza 6 · 0⤊ 0⤋
well done mastermi..
2007-12-16 03:15:26 · answer #3 · answered by Ahmed Zia 3 · 0⤊ 0⤋