If all of the energy from a 60-watt bulb was put into 1 gram of water at room temperature for 2 seconds, how?

Question

much would the temperature of the water increase?

Answer 1

60 watts = 60J/s so in 2 seconds you have 120j
the specific heat of water =4.185J/g
so 120 =4.185 dt
dt =120/4.185 =28.7°

Answer 2

Despite the codswallop given above, here's your answer.
60W = 60 J/s x 2s = 120 J = 120J ÷ 4.184J/g/°C = 28.7°C
= 1 gram of water increased by 28.7°C after 2 seconds..

Answer 3

FIRST.... you have to Measure the CALORIC OUTPUT.... of that 60-Watt Blub!

SECOND.... then Calculate the BTU..... applied to the VOLUME... of the water!

BUT......

ONCE AGAIN....

Global Warming MEANS "World Wide Warming!" It is ONLY A Political Term = NOT based in Real Science!

The EARTH is covered by "Three Quarters WATER!" Basic Science, it takes ONE-Btu to raise One Cubic Centimeter ONE Degree Centigrade!

HOW many "Gazillion Cubic Centimeters are there ONLY on the Surface of Planet Earth COVERED by 3/4 Water?"

HOW many Btu's would it take TO RAISE THE SURFACE TEMPERATURE ONE DEGREE?

DO THE MATH!

And, were are the Million TEMPERATURE MEASURING SITES on the Many Oceans THAT TELL US THAT THE OCEAN TEMPERATURES ARE RISING? Not!

Oh yes, POLAR temperatures have varied LESS Than one degree in the past 100-Years. Noticed I said VARIED, = NOT RISEN!

Thanks, RR