A 18 kg block is in equilibrium on an incline of angle = 45°. Find Fn of the incline on the block.
N
2007-12-16 02:32:34 · 3 answers · asked by NiNi 2 in Science & Mathematics ➔ Physics
Align your coordinats system such that the x-axis is parallel to the surface of the plane and the y-axis normal to it. The forces are
the normal force N, along the +y axis
the friction force μN, along the -x axis
the gravitational force mg, straight down with components mg sin 45 on the +x axis and mg cos 45 on the -y axis.
The net force on each axis is zero, so
N = mg cos 45
μN = mg sin 45
It looks like all you're asking for is N, the normal force.
2007-12-16 02:48:45 · answer #1 · answered by jgoulden 7 · 0⤊ 0⤋
Fn=mgcosx
Fn=18(9.8)cos45
Fn=124.7336362 N
2007-12-16 02:54:56 · answer #2 · answered by Murtaza 6 · 0⤊ 0⤋
The gravitational force is, in this case, resolved into components of equal magnitude: a force down the incline, and a force normal to the incline. The magnitude of each of these will be 18/sqrt(2).
2007-12-16 02:50:16 · answer #3 · answered by Anonymous · 0⤊ 0⤋