Hi,
I need to find the value of x in this equation and I am clueless! An explanation would be great!
0 = (x-2)^2-16
Thanks!
2007-12-16 01:46:38 · 5 answers · asked by Jack D 1 in Science & Mathematics ➔ Mathematics
Could someone give me an explanation. I am not to sure why it could equal -4 or +4.
Thanks.
2007-12-16 01:57:43 · update #1
tht's a simple quadratic if m not hugely wrong..
(x-2)^2=16
x-2=+4 or x-2=-4
taking +4...x=6
taking -4,..x=-2...got it?
2007-12-16 01:50:04 · answer #1 · answered by ishita 1 · 0⤊ 0⤋
The x is x-2 - 12-2
2007-12-16 09:49:17 · answer #2 · answered by Anonymous · 0⤊ 0⤋
The final solution is all the values that make (x-6)(x+2)=0 true.
x=6,-2
2007-12-16 09:55:35 · answer #3 · answered by stringsdepotplus 2 · 0⤊ 0⤋
Plug a=x-2, b=4 into
a^2 - b^2 = (a - b)(a + b)
a^2 - b^2 = (x - 2)^2 - 4^2 = [(x - 2) - 4][(x -2) + 4] = (x - 6)(x + 2)
0 = (x - 2)^2 - 16
Thus, (x -6)(x + 2) = 0
Ant thus, x=6 or x=-2
2007-12-16 09:51:05 · answer #4 · answered by Amit Y 5 · 1⤊ 0⤋
0 = x2 - 4x + 4 - 16
x2 - 4x + 4 = 16
x2 - 2x - 2x + 4 = 16
x(x - 2) -2(x - 2) = 16
(x-2) (x-2) = 16
x = 18
2007-12-16 10:12:02 · answer #5 · answered by Anonymous · 0⤊ 0⤋