help please!
6x^2 + 19x + 8 = 0
a. x = 3/8; -177/50
b. x = -3/8; 177/50
c. x = 8/3; 1/2
d. x = -8/3; -1/2
2007-12-15 19:19:47 · 8 answers · asked by anna 1 in Science & Mathematics ➔ Mathematics
ax²+bx+c=0
x= -b ±√ b²-4ac/2a
x= -19 ±√361-192/12 = -19+13/12 = -1/2
x= -19-13/12 = -32/12 = -8/3 = - 2.67
d
2007-12-15 19:22:12 · answer #1 · answered by iceman 7 · 3⤊ 4⤋
The variable x has two real solutions. The first is -0.5 and the second is -2.6 (repeating, don't forget the line over the six).
2007-12-16 03:31:22 · answer #2 · answered by PharmMan 2 · 0⤊ 1⤋
3x 8
x
2x 1
(3x+8)(2x+1) = 0
So, x=-8/3 or -1/2
d
2007-12-16 03:42:03 · answer #3 · answered by cheng 1 · 0⤊ 1⤋
Iceman has the best answer IMO, and the 'teacher' should take an English, or grammar class or two.
2007-12-16 04:18:19 · answer #4 · answered by screaming monk 6 · 1⤊ 2⤋
(-b+-(b2-4*a*c))/2*a
a=6
b=19
c=8
d. x = -8/3; -1/2
2007-12-16 03:28:20 · answer #5 · answered by Garfield 2 · 0⤊ 1⤋
x = [- 19 ± â(19 ² - 192) ] / 12
x = [ -19 ± â(169 i ²) ] / 12
x = [ -19 ± 13 i ] / 12
None of above answers?
2007-12-16 04:58:49 · answer #6 · answered by Como 7 · 2⤊ 2⤋
use quadratic equ
x=-19+-sqrt169 all over12
=-19+-13 all over 12
=-2 2/3,-1/2
answer is d
2007-12-16 03:25:16 · answer #7 · answered by someone else 7 · 1⤊ 6⤋
Answer is D
2007-12-16 03:23:13 · answer #8 · answered by brokenipoduser 3 · 0⤊ 3⤋