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A sphere of radius 3 cm has an unknown amount of charge uniformly distributed over its volume. If the electric field at a distance 10 cm from the center of the sphere is 3 x10-3 N/C and points radially inward, what is the total charge on the sphere?

i'm trying to treat the sphere as a point charge, but i'm not getting a reasonable answer.

2007-12-15 18:40:25 · 4 answers · asked by Anonymous in Science & Mathematics Physics

nm i got it

2007-12-15 18:43:01 · update #1

4 answers

Hmmm...for charge uniformly distributed across a sphere you can indeed treat that as a point charge at the center of the sphere (proof by Gauss's Law). The charge is found using...

E = k q / r²

( 3 x 10^-3 N / C ) = ( 9 x 10^9 N m² / C² ) ( q ) / ( .10 m )²

I get about -3.3 x 10^-15 Coulombs (negative as the field is directed towards the sphere).

2007-12-15 18:47:49 · answer #1 · answered by jgoulden 7 · 1 0

You are correct considering that the charged sphere behaves outside it as a point electric charge located at its center.
From Couilomb's formula in vaccum
E=q/4x3.14.epsilon(zero)rr
where q is the electric charge in As, r the distance from the center to the point where the electric field is measured in m and epsilon(0) the permitivity of empty space (you should look for a source of its value in IS units).

2007-12-15 18:51:37 · answer #2 · answered by Anonymous · 0 0

Are you remembering to handle the spheres as element fees? Then do your calculations based on the gap between centerpoints c1*c2 --------- (opposite signs and symptoms = internet charm) d^2 wish that enables

2016-11-03 10:43:37 · answer #3 · answered by ? 3 · 0 0

no fair...

I was going to devote my life to finding the answer for you and you went and figured it out!

so smarty pants whats the correct answer?

we're dying to know...

2007-12-15 18:46:13 · answer #4 · answered by whoopswhatever 4 · 1 0

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