How do I determine the mole ratio of oxygen to tin?

Question

The directions state:
Determine the mole ratio of oxygen to tin in the product.

I figured out that there is:
0.169334 mol Sn
and
0.003125 mol O

But what's the product?
And how do I find the mole ratio?

Please help! Thanks :)

Answer 1

Get out your calculator. Enter the moles of Oxygen, the divide sign, the moles of tin, and the equal key. The answer is the ratio you want, although it will be in decimal form. I got .018, rounded to the nearest thousandth. You can write that as 18:1000. If the product is tin oxide, it should be 1:2 (formula SnO2), or 2:3 (formula Sn2O3). Those are the normal compounds of tin oxide. So I don't know what your product would be from the numbers you gave in your question.