Maybe I'm reading it wrong, but doesn't this read, 9x to the power of negative four equals zero? Therefore, doesn't x have to equal zero??
2007-12-15 17:12:04
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answer #1
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answered by keshequa87 6
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X = 0
2007-12-15 17:00:43
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answer #2
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answered by DJE 3
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Step One: (1/9x^4)=0 --> gets rid of the negative power
Step Two: 9*(1/9x^4)=9*0 --> gets rid of fraction
Step Three: 9x^4=0
Step Four: x=0 --> has to, since only 0^4=0.
2007-12-15 16:58:58
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answer #3
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answered by boxster1990 1
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I got no solution because if you divide 0 by 9, you get x^-4=0 and x^-4 is the same as 1/x^4, and if you multiply x^4 by zero on the other side, you get 1=0 which is impossible. Therefore, there's no solution.
2007-12-15 17:06:49
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answer #4
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answered by Peter 2
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9x^ -4=0. 9( 1/x^4)=0.
0.
2007-12-16 02:13:20
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answer #5
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answered by Sasi Kumar 4
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You mean 9x to the power of 4 right?...
I'm guessing that's equal to (9)/(x^4) but I don't know how to solve that so ya...
2007-12-15 17:43:01
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answer #6
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answered by Anonymous
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9x² - 4 = 0
That's the difference of two squares, so the solution is
( 3x + 2 ) ( 3x - 2 ) = 0
The roots are x = 2/3 and x = -2/3.
2007-12-15 17:09:32
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answer #7
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answered by wudup 1
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9x^-4 is the same as 1/(9(x^4)) therefore x needs to be approaching infinity for the statement to be true. Don't be fooled. x is NOT equal to zero.
2007-12-15 17:01:11
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answer #8
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answered by solo 4
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I'm guessing that you meant
9x² - 4 = 0
That's the difference of two squares, so the solution is
( 3x + 2 ) ( 3x - 2 ) = 0
The roots are x = 2/3 and x = -2/3.
2007-12-15 16:56:01
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answer #9
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answered by jgoulden 7
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9x^-4 is the same as 1/(9x)^4, so it is the same as 1/6561x^4, so no solution.
2007-12-16 16:41:40
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answer #10
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answered by Anonymous
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= 2/3 and x = -2/3.
2007-12-15 17:12:16
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answer #11
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answered by aj m 1
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