Calclas - Bewildering Question?

Question

Bewildering Math assignment


A vertical radio antenna is to be built on a hill which makes an angle of 6 (degrees) with the horizontal. If guy wires are to be attached at a point that is 75.0 m up on the antenna and at points 50.0 m from the base of antenna what will be the length of guy wires which are positioned up and directly down the hill ?

This is all that i have . =( if possible could u show some working out

Answer 1

Actually it's a simple trigonometry problem. Triangles have three sides and three angles. If you know ANY three of these values, the other three are easily found.

You have a pair of triangles in which you know the lengths of two sides and the value of the angle between them.

For the first triangle is

75 meters for the vertical side
50 meters for the second side (going downhill)
96 degree angle between them

For the second it's

75 meters for the vertical side
50 meters for the second side (going uphill)
84 degree angle between them

If you need more hints, look up the Law of Cosines and the Law of Sines.

Answer 2

Let : r= diagonal dist from base of antenna
to guy wire tie-in point at bottom
L= length of guy wire
r = 50/cos 6
r= 50.275
L^2= r^2 + 75^2 - 2cos96*r*75
L = 94.56 m