At a specific engine rpm, an automobile engine provides a constant force that is applied to the automobile. If the car is traveling on a horizontal surface, does the car accelerate when this force is applied? Explain.
My answer: F = ma. Since F is constant and m is constant, then a is also constant. So, I guess the car DOES NOT accelerate? Is this right? Is the explanation right? I'm not sure... =|
Thanks!
2007-12-15 16:28:03 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Physics
What do you mean by "accelarate" Because if a body experiences a net force it expeiences. First you say that a is constant then you say that the car does not accelarate.The engine provides a constant force so the car experiences a constant accelaration.
Heres the explanation
When the car engine applies a constant force it experiences accelaration because as you said
f=ma
Here f is not equal to 0
So a is not 0 because a=f/m
So this means the car experiences an accelaration due to the engine. But if the frivtional force is able to cancel out the force of engine than the net force will be 0 and the car will not experience any accelaration.
2007-12-15 18:41:01 · answer #1 · answered by Vaibhav Dwivedi 4 · 0⤊ 0⤋
you are right that f is constant and m is constant then a is also constant. but for acceleration its not about whether or not a is constant; its about whether a is zero or not zero. whenever a is NOT zero, the object is moving or about to move, and its speed is changing. the only time there is no acceleration is when a=zero. in your problem here A is not zero.
if a is not zero but its some constant number like....21.4 then
the object is accelerating. its speed and/or direction is changing.
if a is not zero but its not constant the object is still accelerating.
constant or not constant, if a is not zero there is acceleration.
2007-12-15 17:54:57 · answer #2 · answered by Anonymous · 0⤊ 0⤋
This problem is really confusing me as well.What is the question? I can only guess that the question is: at what angle is the rope attached to the box. Is this the question? If so, answer as follows: Because the box moves at a constant velocity, the resultant or net force is zero. Therefore the applied force in a horizontal direction must be equal to the friction force: Applied force horizontal direction = 25N 25N is the horizontal component of a 43N force at an angle Θ with the ground. Solve for Θ. cos Θ = 25/43 cos Θ = 0.5814 Θ = 54.45° above the horizontal The rope was at an angle of 54.45° above the horizontal
2016-05-24 04:03:09 · answer #3 · answered by cherly 3 · 0⤊ 0⤋
The car will accelerate until friction and windage forces cancel the force provided by the engine.
a = 0 iff F = 0
2007-12-15 17:13:24 · answer #4 · answered by Helmut 7 · 0⤊ 1⤋
You answered your own question. A is constant. What is a? Acceleration. So you have just said. "Acceleration is constant i.e. non-zero", and if net force is non-zero then acceleration is non-zero. You do accelerate.
2007-12-15 21:48:45 · answer #5 · answered by gae_bulg 3 · 0⤊ 0⤋
Assuming that the car is already traveling at that speed it will be constant.
Of course if it is a change in RPM that is applied, then there will be a change in the speed. It will increase or decrease until stasis is achieved.
2007-12-15 16:52:08 · answer #6 · answered by Light Knight 7 · 0⤊ 1⤋
"engine provides a constant force" - No acceleration.
2007-12-15 16:33:37 · answer #7 · answered by Anonymous · 0⤊ 3⤋
It's totally correct. You may go into details on engines. But that's enough.
2007-12-15 16:41:13 · answer #8 · answered by ? 2 · 0⤊ 2⤋