1.x+3y=5
x+4y=6
2.p-3q=-1
5p+16q=5
3. 300x-y=130
200x+y=120
2007-12-15 16:21:20 · 2 answers · asked by Frannie 2 in Science & Mathematics ➔ Mathematics
it was 3 separate problems not 1 problem :(
2007-12-15 16:43:07 · update #1
x+4y=6
x+3y=5
Subtract the lower equation from the upper to get y = 1; then x = 2.
5p+16q=5
p-3q=-1
Multiply the bottom equation by -5...
5p+16q=5
-5p+15q=15
...now add the two equations to get
31q = 20 or q = 20/31
300x-y=130
200x+y=120
Add the equations to get
500x = 250
x = 1/2
2007-12-15 16:27:27 · answer #1 · answered by jgoulden 7 · 0⤊ 1⤋
x+4y=6
x+3y=5
Subtract the lower equation from the upper to get y = 1; then x = 2.
5p+16q=5
p-3q=-1
Multiply the bottom equation by -5...
5p+16q=5
-5p+15q=15
...now add the two equations to get
31q = 20 or q = 20/31
300x-y=130
200x+y=120
Add the equations to get
500x = 250
x = 1/2 hope this helped
2007-12-16 00:35:53 · answer #2 · answered by bright 2 · 0⤊ 0⤋