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2007-12-15 16:09:59 · 8 answers · asked by diva 1 in Science & Mathematics ➔ Mathematics
4x² - 13x + 3 = 0
(4x - 1)(x - 3) = 0
x = 1 / 4 , x = 3
2007-12-15 21:25:53 · answer #1 · answered by Como 7 · 2⤊ 3⤋
4x^2-13x= -3
4x^2-13x +3= 0
4x^2-12x -x + 3= 0
4x (x-3) -1(x - 3)= 0
(4x-1)(x-3)=0
4x-1 = 0 or x-3=0
Because if the overall product is 0, then one of the terms in the form axb HAVE to be zero.
4x=1 or x=3
x=1/4 or x=3
2007-12-15 16:13:58 · answer #2 · answered by Anonymous · 0⤊ 2⤋
first bring all variables to one side and set to 0
4x^2-13x+3=0
now factor
(4x-1)(x-3)=0
x=0 at 1/4 and 3
2007-12-15 16:13:22 · answer #3 · answered by shadowca1964 4 · 0⤊ 2⤋
4x^2 - 13x = -3
4x^2 - 13x + 3 = 0
(4x - 1)(x - 3) = 0
x = 1/4, 3
2007-12-15 16:48:33 · answer #4 · answered by jimbob 6 · 0⤊ 2⤋
4x^2-13x+3=0
4=1*4
3=-1*-3
1*-1+4*-3=-13
(x-3)(4x-1)=0
2007-12-15 16:16:13 · answer #5 · answered by chernshinn 1 · 0⤊ 2⤋
4x² - 13x = -3
4x² - 13x + 3 = 0
4x² - 12x - x + 3 = 0
4x(x-3) -1(x-3) = 0
(4x-1)(x-3) = 0
4x- 1 = 0
x = 1/4
x-3 = 0
x = 3
x = {1/4, 3}
2007-12-15 16:13:32 · answer #6 · answered by gudspeling 7 · 1⤊ 2⤋
4x^2 - 13x+3=0
4x^2-12x-x+3=0
4x(x-3) -(x-3)=0
=> x=3,1/4
2007-12-15 16:12:40 · answer #7 · answered by krishna t 2 · 0⤊ 2⤋
i can do it...but i just dont feel like doing it lol...
you just have to move the -3 over to the left side and then use quadratic formula...
2007-12-15 16:13:34 · answer #8 · answered by Bad Man Kalia 2 · 0⤊ 2⤋