I've only been to one! And my works one has been cancelled. :o(
2007-12-15 14:10:14 · 17 answers · asked by farleyjackmaster 5 in Society & Culture ➔ Holidays ➔ Christmas
one. been on that
2007-12-16 05:28:36 · answer #1 · answered by Anonymous · 0⤊ 0⤋
2
2007-12-15 14:17:43 · answer #2 · answered by Kate 3 · 0⤊ 0⤋
I've only been to one too!! Last night !! I drank a little to much and stole Santas suite beard the works and crashed another party just down the hall from ours (Work Party) Man you want to go to Christmas parties get yourself a suite everybody welcomes you. I was dancing with everybody. lol â¥
2007-12-15 14:22:41 · answer #3 · answered by Polar Molar 7 · 2⤊ 0⤋
2 work parties and 2 family parties
2007-12-16 02:08:30 · answer #4 · answered by fraggle 3 · 0⤊ 0⤋
There is one on my street tonight but my partner was hit by a truck a few weeks ago and can't move well, so I am spending it with him .... We would have gone otherwise.
We always have Christmas eve dinner with my mom's childhood friend and her family... so that will be another (subdued) party. (It's tradition and I love it!).
I doubt there will be others
2007-12-15 14:17:34 · answer #5 · answered by elementoflife 6 · 0⤊ 0⤋
Have not been to any. Sorry. Merry Christmas, I will enjoy Christmas Day when the family come.
2007-12-17 03:13:42 · answer #6 · answered by Sally Anne 7 · 0⤊ 0⤋
not one! My husband has had 3!! I was invited to none of those, I had a works one, but it's on the 23rd- too close to xmas so I refused
2007-12-15 18:32:18 · answer #7 · answered by emily_jane2379 5 · 0⤊ 0⤋
im going to at least three, 2 are with my family for xmas and xmas eve, and ill be with friends on new years !
2007-12-15 14:14:08 · answer #8 · answered by Texas Boy 6 · 0⤊ 0⤋
none.. im such a loner.. haha oops i forgot i will be going to one- a family reunion on the christmas day itself..
2007-12-15 14:16:23 · answer #9 · answered by camed 3 · 0⤊ 0⤋
like, 50!!!! Almost all of my friends are throwing parties. Ahhhhh!
2007-12-15 14:22:03 · answer #10 · answered by ari d 2 · 0⤊ 0⤋