I got -1 but supposedly thats wrong.. does anybody know how to solve it
can you square top and bottom?
thanks for your help
2007-12-15 13:50:58 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
√ (- 25 / 5 i )=√ ( 25 i ² / 5 i) = √ (5 i )
2007-12-19 09:59:02 · answer #1 · answered by Como 7 · 0⤊ 0⤋
The square root of -25 is 5i, it could also be written as 5 times the square root of -1. since thats what i represents
2007-12-15 21:59:07 · answer #2 · answered by badbean 2 · 0⤊ 0⤋
When you take the square root of (a/b), you can do sr(a)/sr(b). In this case you probably want to simplify first though. This could either mean sr[(-25)/(5i)] or sr[(-25/5)i].
If it's the first case, you get sr[5i] = sr(5/2) + sr(5/2)i.
If it's the second, you get sr[-5i] = sr(2.5) - sr(2.5)i.
EDIT: If you mean sr(-25)/5i, then you just get 1.
2007-12-15 22:00:36 · answer #3 · answered by Anonymous · 0⤊ 0⤋
-25/5i = -5/i = -5i/i^2 = -5i/(-1) = 5i
Therefore sqrt = sqrt (5i)
2007-12-15 21:54:47 · answer #4 · answered by ozperp 4 · 0⤊ 0⤋
Therefore sqrt = sqrt (5i)
2007-12-16 02:32:42 · answer #5 · answered by Rock star 2 · 0⤊ 0⤋
sq rt of 5i
2007-12-15 21:58:17 · answer #6 · answered by MALATHI VEDAGIRI 2 · 0⤊ 0⤋
(5i)^2 / 5i = 5i
so sqrt(5i) is the answer
2007-12-15 21:58:40 · answer #7 · answered by none2perdy 4 · 0⤊ 0⤋