Describe the point at which glucose is completely oxidized during cellular respiration.
Is it the Citric Acid Cycle (Krebs Cycle) or the Electron Transport Chain (ETC), and why?
2007-12-15 13:16:24 · 2 answers · asked by goldigga 2 in Science & Mathematics ➔ Biology
Glucose is completely oxidized at the end of the Kerbs cycle. The formula for glucose is C6H12O6. In the general equation of cellular respiration, 6 CO2 are released. Two of the carbon dioxides are released in the acetyl CoA step and the other four in the Krebs cycle. Since glucose is a six carbon sugar, when 6 CO2 are released, the 6 carbons previously on glucose are now in the form of CO2, and thus released from the body. The electrons that were on glucose are now mainly in the form of NADH and FADH2, which then go on to donate its electrons to the ETC.
2007-12-15 14:09:32 · answer #1 · answered by Anonymous · 3⤊ 0⤋
Should be the ETC, since the chain carries the electrons to be used for other purposes inside the cell... the electron source (glucose) would have been completely oxidized to CO2 using a TEA.
2007-12-15 13:23:27 · answer #2 · answered by ¿ /\/ 馬 ? 7 · 2⤊ 0⤋