A 16.9 kg block is dragged over a rough, horizontal surface by a constant force of 159N acting at an angle of?

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A 16.9 kg block is dragged over a rough, horizontal surface by a constant force of 159N acting at an angle of?

29.1 degrees above the horizontal. The block is displaced 96.5m, and the coefficient of kinetic friction is 0.169. The acceleration of gravity is 9.8m/s^2. Work= 13406.7241J.
Find the magnitude of the work done by the force of friction. Answer is Joules.

2007-12-15 08:39:59 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Physics

1 answers

Wf=f s

(Let's see
Wt= F cos(29.1) s
Wt= 159 cos(29.1) x 96.5=13400 J. ( 3 SF only)]

Tthe work done by friction is
Wf= umg= 0.169 x 16.9 x 9.8=28.0 J

2007-12-15 09:32:59 · answer #1 · answered by Edward 7 · 0⤊ 0⤋