How do you put a line in point-slope form to slope-intercept form?

Question

Here is my equation in point-slope form:

y - 6 = (3/2) * (x + 2)

please put it in slope-intercept form, and explain how you did it.
Thanks!

Answer 1

Slope intercept form is found by putting y on the right all by itself, and simplifying.

y - 6 = (3/2) * (x + 2)
y = (3/2) * ( x + 2 ) + 6 Add 6 to both sides
y = (3/2) * x + 3 + 6 Multiply 3/2 through (x + 2)
y = (3/2) * x + 9 Add up remaining constants

Answer 2

Rearrange the equation so it has the variety y = mx + b the place m is the slope and b is the y-intercept (i.e., the cost of y while x = 0). y - 6 = (3/2)(x + 2) upload 6 to the two aspects of the equation: y = (3/2)(x + 2) + 6 Do the muliplication: y = (3/2)x + 3 + 6 y = a million.5x + 9 The slope of the line is a million.5 and it intersects the x axis at (0,9)

Answer 3

y-6 = (3/2) (x) +3
y = (3/2)(x) + 9

On the right, multiple each term (x and 2) by 3/2. Then solve for Y, so add 6 to each side. they you have slope-intercept form. y=mx+b.

m is slope...3/2
b is the y intercept...9

Answer 4

Multiply the slope through to (x+2)

to get y - 6 = 3x/2 + 6/2

Simplify to get y-6 = 3x/2 +3
Move the 6 to the other side.
y=3x/2 + 9