The question is "find the equation of the line passing through (0, -3) with slope 3/4th y= ?? Thanks sooo much!!!
2007-12-15 07:30:17 · 4 answers · asked by hipmamma25 1 in Science & Mathematics ➔ Mathematics
y = ( 3 / 4 ) x + b
You know one point on the line is ( 0, -3 )
-3 = ( 3 / 4 ) ( 0 ) + b
-3 = b
So you now have
y = ( 3 / 4 ) x - 3
as the equation for your line.
2007-12-15 07:36:14 · answer #1 · answered by jgoulden 7 · 1⤊ 0⤋
Since this is a take-home, I can't give you the answer, but:
Slope-intercept form of a line is y=mx+b
where m=slope and b= y-intercept
Once you know m, you can plug in (x,y) = (0,-3) to get
b = y - mx
If you get b first, you can solve m = (y-b)/x
2007-12-15 15:37:19 · answer #2 · answered by halac 4 · 0⤊ 0⤋
line through (0, --3) with slope 3/4 is
y = 3x/4 + 3(0)/4 + (--3)
Or y = 3x/4 -- 3
2007-12-15 15:43:34 · answer #3 · answered by sv 7 · 0⤊ 0⤋
y=mx+b where m=slope
y=(3/4)x-3
2007-12-15 15:56:17 · answer #4 · answered by Padambi 3 · 0⤊ 0⤋