e^(x +3)=10^(4-x)
please show work. thanks. i got to x +3=(4-x)ln10 if that is right. idk. i know multiply= add so what would it b?? thanks!!
2007-12-15 06:42:37 · 5 answers · asked by dcgirl 3 in Science & Mathematics ➔ Mathematics
e^(x +3)=10^(4-x)
As you already know, take the natural log of both sides...
x + 3 = ln ( 10^ ( 4-x ) )
Using the property of logs: log ( a ^ b ) = b log ( a )...
x + 3 = ( 4 - x ) ln ( 10 )
You now have a linear equation in x.
x + 3 = 4 ln ( 10 ) - x ln ( 10 )
x ( 1 + ln ( 10 ) ) = 4 ln ( 10 ) - 3
x = ( 4 ln ( 10 ) - 3 ) / ( 1 + ln ( 10 ) )
2007-12-15 06:47:23 · answer #1 · answered by jgoulden 7 · 0⤊ 0⤋
Take ln,
x+3 = (4-x)ln10
=> x = (4ln10 - 3)/(1 + ln10)
2007-12-15 14:48:37 · answer #2 · answered by sahsjing 7 · 0⤊ 0⤋
you are right.
x + 3 = (4-x)ln(10)
(x+3) = (4-x)(2.3) (since ln(10) = 2.302)
x+ 3 = 9.2 - 2.3x
3.3x = 6.2
x = 6.2/3.3 = 1.88
2007-12-15 14:52:47 · answer #3 · answered by mohanrao d 7 · 0⤊ 0⤋
ure a big nerd if ure tryin to work tht out
2007-12-15 14:45:46 · answer #4 · answered by Anonymous · 0⤊ 0⤋
i agree with the second guy
2007-12-15 14:51:43 · answer #5 · answered by cheerios 3 · 0⤊ 0⤋