If a corpse weighs 200 pounds and he or she is placed in a casket 2 foot wide, 7 foot long and 1 foot high which weighs 2 pounds per cubic feet, what is the total weight that has to be lifted?
2007-12-15 06:37:05 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
I think it is 228 pounds because you must find the volume by doing 2 x 7 x 1 = 14 cubic feet. Since one cubic foot is 2 pounds, you must do 14 x 2 = 28. Don't forget to add the corpse's weight! 28 + 200 = 228 pounds!
2007-12-15 07:17:30 · answer #1 · answered by idkmybffrose 3 · 0⤊ 0⤋
The volume of the casket in cubic feet is 2 x 7 x 1 = 14 cubic feet. At 2 lbs per cubic foot, that's 28 pounds. So the total that must be lifted is 228 pounds.
2007-12-15 14:40:41 · answer #2 · answered by jgoulden 7 · 0⤊ 0⤋
Total Weight = weight of corpse + weight of casket
weight of corpse = 200 pounds
weight of casket = Volume x 2
=(2x7x1 )x2=28 Pounds
Total Weight = 200 + 28 = 228 Pounds
2007-12-15 14:44:31 · answer #3 · answered by Murtaza 6 · 0⤊ 0⤋
Find the weight of the casket.
Volume of the casket is 2*7*1 = 14 ft^3 * 2lbs /ft^3 = 28lbs
Add the weight of the corpse to get 228 lbs
2007-12-15 14:41:44 · answer #4 · answered by Freddy 2 · 0⤊ 0⤋
total weight
= corpse + casket
= 200 lb + volume*density
= 200 lb + 2*7*1*2 lb
= 200 lb + 28 lb
= 228 lb
2007-12-15 14:48:39 · answer #5 · answered by sv 7 · 0⤊ 0⤋
200+2(7x1x2)
200+2(14)
200+28
228
2007-12-15 14:47:47 · answer #6 · answered by Anonymous · 0⤊ 0⤋