in math i'm taking patterns and can't do it ! cane you help?
but, i have to solve them in more then one way!
1,3,9....one of them: !1,3,9.....27,81,243. can anyone come up with another way? next one : 0,1,10....... and the one after that is:2,3,5,..... help ,please!!!
2007-12-15 06:35:53 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
how about 1,3,9 .... can anybody help??
2007-12-15 06:47:32 · update #1
i mean other the that!
2007-12-15 06:48:12 · update #2
how about this one:1,1,2..... i wrote down 1,1,2,2,3,3,... is it right??
2007-12-15 07:12:28 · update #3
Looks you got the first one; 1, 3, 9, 27, 81, 243, ... are the powers of three.
0, 1, 10, 11, 100, 101, 110, 111... are the integers expressed in binary.
2, 3, 5, 8, 13, 21, ... is a part of the Fibonacci sequence (each term is the sum of its two predecessors).
2007-12-15 06:42:07 · answer #1 · answered by jgoulden 7 · 0⤊ 0⤋
1, 3, 9, 19, 33, 51 etc is a sequence where you add 4x-2 to the previous number in the sequence, and x is the position in the sequence
eg to 1 you add (4*1 - 2) = 2 to get 3
to 3 - the 2nd in the sequence - you add (4*2 - 2) = 6 to get 9
to 9 - the 3rd in the sequence - you add (4*3 - 2) = 10 to get 19 and so on....
2007-12-15 14:57:17 · answer #2 · answered by ozperp 4 · 0⤊ 0⤋
1st one, alternate: 1, 3, 9, 19, 33,... adding alternate even numbers 2 6 10 14 etc.
2nd one, alternate: 0, 1, 10, 100... powers of 10.
3rd one, alternate: 2, 3, 5, 7, 11, 13... prime numbers.
2007-12-15 14:48:33 · answer #3 · answered by laurahal42 6 · 0⤊ 0⤋
for the last one, you can add 2 to 3. then add 3 to five. not necessarily add the two preceders but add one more. first u added 2, then 3, then 4. ect
2007-12-15 14:48:18 · answer #4 · answered by cheerios 3 · 0⤊ 0⤋