how to use the Pythagorean Theorem to find the length of a diagonal of a rectangle with side lengths and t.?

Answer 1

the formula is a^2+b^2=c^2. Take the side of the rectangle and square it + the top leg is the rectangle and sqaure it. Take this value and square root is and that is your value of the c^2, the diagnol of the rectangle.

Answer 2

Draw a line (a diagonal) between opposite corners of the rectangle. Now you have two right triangles.

the pythagorean theorem = the square of the hypotenuse of a right triangle (side opposite the right angle) is equal to the sum of the square of the 2 sides,
or c^2 = a^2 + b^2, with a and b the two side lengths.
so the square root of (side A squared plus side B squared) is the length of the diagonal.

Answer 3

if the dimensions of one factor is 8 and the diagonal is 10 the dimensions of the different factor is 6. hence the element of the rectangle is 40 8 a carpentry trick for checking if an perspective is ninety tiers is to degree 3 down one factor and four down the different factor - if the diagonal between those 2 factors is 5 then the attitude between the three factor and the 4 factor is 9 tiers

Answer 4

Diagonal equals the square root of (length squared) plus (width squared).

So if length was 5 and width was 4, the diagonal would be the square root of 25 + 16 = 41

Sq root of 41 = 6.40 (to 2 dec places)

Answer 5

use the 2 given side lengths as your legs (the A and B) use the t as your hypotenuse[ the rectangle cut in half diagnoly (C)] so it should say:
(one side)^2 + (other side)^2 = t^2
square the 2 values and add them together. then find the square root of that answer and the exponent on the t cancels out.
answer=t
if the answer you get isn't a perfect square, you have to simplify it under the radical.

Answer 6

if you look at a rectangle with a diagonal, you can see it is divided into two identical right angle triangles.
you can use these triangles like anyother right triangle to find the diagonal.
two connecting (the top and one side let's say) sides act as a and b
a^2=B^2=c(or the diagonal)^2

Answer 7

pretend that this is a triangle


!\
!.....\
!........\
!.............\
!...................\
!_____________\


side (!) = 4

side (_)= 5

now 4= a and 5= b

*= squared

a* + b*= c*

c*= diagonal

4* + 5*=?

16+25=41

now u have to find the square root of 41.


sqrt= 6.403

c*= 6.4.................. so side (\)= 6.4

the measure of the diagonal is 6.4