A horizontal force of 5 N accelerates a 4 kg mass, from rest, at a rate of 0.5 m/s^2 in the positive direction. What frictional force acts on the mass? What friction acts on the mass? What is the coefficient of friction for the surfaces in contact?
Please show and explain all work. Please show the formula or formulas that were used.
2007-12-15 03:37:41 · 2 answers · asked by Kantilal P 1 in Science & Mathematics ➔ Physics
We know that Ft=ma
The balance of forces is the force acting on the object less the frictions force f
Ft=F - f
f= F- Ft= F - ma
f= 5 - 4x 0.5= 3N
The friction force is a product of normal to the surface force W (weight in this case) and coefficient of friction u
f=uW
u= f/W= 3/(4 x 9.81)
u=0.076
2007-12-15 04:13:21 · answer #1 · answered by Edward 7 · 0⤊ 0⤋
i agree with Edward
2007-12-15 15:41:31 · answer #2 · answered by Ahmed Zia 3 · 0⤊ 0⤋