thanks.
2007-12-15 02:41:56 · 13 answers · asked by cew613 2 in Science & Mathematics ➔ Mathematics
ahh i am sorry (x+7)(x-1)=(x+1)^2
2007-12-15 02:55:07 · update #1
should = 2 my teacher gave us the answers but we have to show work.
2007-12-15 03:06:31 · update #2
should = 2 my teacher gave us the answers but we have to show work.
2007-12-15 03:06:32 · update #3
what if there was a log in there would you solve it the same?
EX: log2 (3x+2)+log2 (x-5)=4
2007-12-15 03:34:49 · update #4
i'm sure you can do tht if you'd try...
2007-12-15 02:44:41 · answer #1 · answered by Anonymous · 0⤊ 3⤋
(x + 7)(x - 1) = (x + 1)(x + 1)
x^2 + 6x - 7 = x^2 + 2x + 1
6x - 7 = 2x + 1
4x = 8
x = 2
2007-12-15 11:14:18 · answer #2 · answered by djned12 3 · 3⤊ 0⤋
if it's (x+1)(x-1)=(x+1)^2 and you're looking for the value of x, then x=-1
2007-12-15 10:46:36 · answer #3 · answered by iLOVEu 1 · 0⤊ 2⤋
(x)(x-1)=(x+1)²
x²-x=x²+2x+1
3x=-1
x=-1/3
2007-12-15 10:47:17 · answer #4 · answered by Murtaza 6 · 0⤊ 2⤋
( x + 1)( x - 1) = (x + 1)^2
x^2 - 1 = x^2 + 2x + 1
-2 = 2x
x = -1
2007-12-15 10:46:34 · answer #5 · answered by Anonymous · 0⤊ 2⤋
(x+7)(x-1)=(x+1)(x+1)
x^2+6x-7=x^2+2x+1
6x-7=2x+1
4x-7=1
4x=8
x=2
2007-12-15 11:58:35 · answer #6 · answered by Anonymous · 0⤊ 0⤋
Just multiply them out. You need a second term in the first binomial, (x+ ?)
2007-12-15 10:45:46 · answer #7 · answered by hayharbr 7 · 0⤊ 2⤋
wrong equation....n if its
(x+1)(x-1)=(x+1)^2....ppl hav given the answr...
:)
2007-12-15 10:51:55 · answer #8 · answered by fakhru 2 · 1⤊ 1⤋
(x+)(x-1)=(x+1)^2
x^2-x=x^2+2x+1
-x=2x+1
3x=-1
x=-1/3
2007-12-15 10:56:48 · answer #9 · answered by manaw 1 · 0⤊ 2⤋
x+? what's that? sorry,seems like your question is just weird or maybe I'm weird,cant help.
2007-12-15 10:46:50 · answer #10 · answered by Huei 2 · 0⤊ 2⤋
(x+7)(x-1)=(x+1)^2
x^2-x+7x-7=x^2+2x+1
-6x-7=2x+1
8x=-8
x=-1
2007-12-15 10:59:56 · answer #11 · answered by iyiogrenci 6 · 0⤊ 3⤋