Indices: (7 / 3)^(-2)?

4 ⤊

(7 / 3)^(-2) ?
Please help.

Any As revison websites will also be helpfull.

2007-12-15 02:02:23 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

(7 / 3)^(-2)
= 1/(7 / 3)^2
=1/ (49/9)
=9/49
Use this rule:a^-n = 1/(a^n)

2007-12-15 02:22:29 · answer #1 · answered by Kenneth Koh 5 · 1⤊ 0⤋

1 / (7 / 3) Â² = 1 / ( 7 Â² / 3 Â² ) = 3 Â² / 7 Â² = 9 / 49

2007-12-15 10:07:03 · answer #2 · answered by Como 7 · 3⤊ 0⤋

9/49

2007-12-15 10:50:39 · answer #3 · answered by someone else 7 · 0⤊ 0⤋

(7/3)^-2=(3/7)^2=9/49.ANS.

2007-12-15 10:43:49 · answer #4 · answered by Anonymous · 0⤊ 0⤋

(7/3)^(-2)
(7/3)^(-1*2)
(3/7)^(2)
3^2/7^2
9/49

2007-12-15 10:22:12 · answer #5 · answered by Balan 1 · 0⤊ 0⤋