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2007-12-14 23:39:55 · 3 answers · asked by Anonymous in Science & Mathematics Chemistry

3 answers

pH = pKa + log ([A-]/[HA])

and under buffer conditions, you can assume that [A-] and [HA] correspond to the amounts that you put there.

Dilution does not affect the ratio inside the bracket, so as long as the buffer assumption is good, it should not affect pH.

2007-12-14 23:52:49 · answer #1 · answered by Facts Matter 7 · 3 0

do no longer forget that pH is in basic terms an worry-free way of asserting the concentration of H+ and OH- ions that are in a answer. So say you initially have 4 mols of H+ ions in one L of answer. in case you upload yet another liter in quantity, you at the instant have 4 mols in 2 L of answer. So the concentration went from 4 M to 2 M. for this reason, even regardless of the undeniable fact that the quotient of NH3/NH4Cl is the comparable, it is interior of a better quantity for this reason affecting the pH of a buffer.

2016-11-03 08:34:34 · answer #2 · answered by ? 4 · 0 0

What I know is that the pH of a buffer is not affected by the addition of a small amount of acid or alkali.

2007-12-14 23:46:44 · answer #3 · answered by dlt 3 · 0 1

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