I came up with:
-7 +/- (sqrt47)
2007-12-14 21:24:09 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
x = [- 7 ± √41] / 2
is answer.
2007-12-16 05:47:49 · answer #1 · answered by Como 7 · 4⤊ 1⤋
By completing the square, you will get
x^2 + 7x + 2 = 0
x^2 + 7x + (7/2)^2 = - 2 + (7/2)^2
(x + 7/2)^2 = - 2 + 49/4
(x + 7/2)^2 = -8/4 + 49/4
( x + 7/2)^2 = 41/4
Take the square root of both sides
x + 7/2 = sqrt 41/2
x = -7/2 + sqrt 41/2
x = ( -7 + sqrt 41)/2
and
x = (- 7 - sqrt 41)/2
2007-12-14 22:28:51 · answer #2 · answered by detektibgapo 5 · 1⤊ 1⤋
Actually, I came up with
[-7 +/- sqrt(41)]/2
2007-12-14 21:27:01 · answer #3 · answered by SoulDawg 4 UGA 6 · 1⤊ 1⤋
x²+7x+2=0
ax²+bx+c=0
x=-b±√ (b²-4ac) / 2a
x=-(7)+√((7)²-4(1)(2) ) / 2(1) = (-7 + √41) / 2
x=-(7)-√((7)²-4(1)(2) ) / 2(1) = (-7 - √41 )/ 2
x= (-7±√41)/2
2007-12-14 21:29:03 · answer #4 · answered by Murtaza 6 · 1⤊ 1⤋
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5x^2 - 7x - 6 = 0
( 5x + 3) (x - 2) = 0
x = -3/5
x = 2
--------------------------------
(5x + 3) (x - 2) = 0
5x^2 - 10x + 3x - 6 = 0
5x^2 -7x -6 = 0
2007-12-14 21:27:23 · answer #5 · answered by diya 2 · 0⤊ 2⤋
b^2-4ac=7^2-4*1*2=49-8=41
x=-7+/-sqrt(41)
2007-12-14 21:48:33 · answer #6 · answered by 315 1 · 1⤊ 1⤋
x=-b +/- sq.rt. of b^2-4ac (all over 2a)
i came up with
x=-7 +/- sq.rt. of 41 (all over 2)
hope this helps^^
2007-12-14 21:32:38 · answer #7 · answered by Anonymous · 1⤊ 0⤋
x1=(-7 + sqrt(41))/2
x2=(-7 - sqrt(41))/2
2007-12-14 21:46:11 · answer #8 · answered by Peyman 2 · 1⤊ 0⤋
linear equation
2007-12-14 21:27:06 · answer #9 · answered by misony 4 · 0⤊ 3⤋