Math help please?

Question

Could you show your work on how to do this please?
8pq^2(2pq – 3p + 5q)

Answer 1

8pq^2(2pq-3p+5q)
16p^2q^3-24p^2q^2+40p^2q^3

Answer 2

do you want me to simplify?
all you need to do is use distributive .
8pq^2(2pq – 3p + 5q)
8(2) = 16. Now p times p is p^2 because you have to imagine that there is an imaginary exp of 1 on it. and whenever you multiply exp, you ADD them. same goes for Q. q^2 times q equals q^3.
do that to each of the numbers and you will get
16p^2q^3-24p^2q^2+40pq^3.
wow, what a long answer. haha.

Answer 3

i may be wrong, but this is the best i can do. just watch the changes.

8pq^2(2pq – 3p + 5q)---multiply each variable
8 x (2 - 3 + 5) x p x (p - p) x q x (q + q)---simplify
32 x p x q x 2q
32pq2q------------re-add ^2
(32pq2q)^2


i got a feeling in my gut i am wrong.....

Answer 4

8pq^2 (2pq - 3p + 5q)

16 p^2 q^3 - 24 p^2q^2 + 40pq^3

now that wasn't hard - was it
numbers to numbers
letters add to letters

Answer 5

I think you want to multiply it out.

8pq^2(2pq) + 8pq^2(– 3p) + 8pq^2(5q)

16p^2q^3 + I think you can finish.

Answer 6

everyone who answered you question is obviously clueless!
^ means to the power so:
your equation is the same as:
(8pq^2)(2pq)-(8pq^2)(3p)+(8pq^2)(5q)=
16p^2q^3-24p^2q^2+40pq^3

Answer 7

I do not know that and I am sorry. I congratulate you thoe for studying maths. :) Keep going and you'll get yourself a good report and career! Another bonus is you will be smart and help other kids that need help.

So keep studying :)

Answer 8

huh thats a toughie

Answer 9

no clue what that problem is saying

Answer 10

is this supposed to be equal to anything?