Epsom salts that are used as a laxative consist of MgSO4 * 7H20. How many grams of Mg are present in 0.0250 mole of MgSO4 * 7H20, which is 9.86% Mg.
The answer I calculated is 0.297g Mg, but I'm not sure if it's correct. Thanks for your help!
2007-12-14 16:03:58 · 5 answers · asked by Steven M 3 in Science & Mathematics ➔ Chemistry
Molar mass MgSO4.7H2O = 120.415 g/mol+ 126.14 g/mol =
246.56 g/mol
Grams of MgSO4 7H2O = 0.0250 mol x 246.56 g/mol =6.16
Grams Mg = 6.16 x 9.86 / 100 =0.608 g
2007-12-14 16:12:04 · answer #1 · answered by Dr.A 7 · 1⤊ 0⤋
I'm not sure why you'd need to know what % of the compound is Mg. The way I'd do it is, if there's 0.0250 mol of the compound, and it's got a single Mg in it, then there's 0.0250 mol Mg. The atomic mass of Mg is 24.305 g/mol, so multiply that by 0.0250 mol and you get 0.608 g Mg.
So I think the answer should be 0.608 g Mg.
2007-12-14 16:11:00 · answer #2 · answered by Amy F 5 · 0⤊ 0⤋
1 mole of epson salt wts 246 g.
So 1/40 of that is 6.1 grams
Since 9.86 pct is Mg by mass, 6.1x.0986= 0.6 gm appx.
2007-12-14 16:23:27 · answer #3 · answered by cattbarf 7 · 0⤊ 0⤋
go find out from a drug dealer
2007-12-14 16:06:00 · answer #4 · answered by Anonymous · 0⤊ 2⤋
idk
2007-12-14 16:06:04 · answer #5 · answered by dietcoke884 2 · 0⤊ 2⤋