Compute the limit: lim as h->0 of sin(2h)/cos(3h)?

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2007-12-14 13:27:39 · 2 answers · asked by swimmertommy 1 in Science & Mathematics ➔ Mathematics

plug 0 in for h

Lim = sin(2*0) / cos(3*0)

Lim = sin(0) / cos(0)

Lim = 0/1

Lim = 0 <== answer

Rec

2007-12-14 13:37:22 · answer #1 · answered by Anonymous · 1⤊ 0⤋

The limit of the denominator as h -> 0 is 1.
So the answer is lim h-> 0 sin(2h) = 0.

2007-12-14 22:04:43 · answer #2 · answered by steiner1745 7 · 0⤊ 0⤋