Find an equation in standard form for line described ?

Question

through the points: (-5,-1) and (3,3)

Answer 1

First use the data points to determine the slope of the line.
slope m = rise/run
= (3- -1)/(3--5)
= 4/8
= 0.5

Use m and (-5,-1) to determine the y-intercept:
y = mx + b
-1 =0.5(-5) + b
y-intercept b = 1.5

Equation of the line:
y = 0.5x + 1.5

Answer 2

First, find the slope. The slope is the difference of the y coordinates divided by the difference of the x coordinates. So,

slope = (-1-3)/(-5-3) = -4/-8 = 1/2

Write the equation in slope-intercept form, y = mx + b, where m is the slope, and b is the y-intercept. Then,

y = (1/2)x + b Need to find b by plugging in a point, say, (3, 3)

3 = (1/2)*3 + b. Solving for b, b = 1 1/2 = 3/2. So, the equation now reads,

y = (1/2)x +3/2 But this is not in standard form yet...

Standard form is written as Ax + By =C, where A, B, and C are integers, and A>0. Rearrange the equation by first multiplying everything by 2 (this gets rid of the fractions)...

2y = x +3. Now rearrange to standard form...

x -2y = -3

Answer 3

Let the general form of the equation is y = ax+b
Substitute these points into the equation:
-1 = -5a +b (1)
3 = 3a +b (2)
Take (2) - (1): 4 = 8a .-> a = 1/2
So b = 3/2
The equation is y = 1/2x + 3/2

Answer 4

slope = (3--1)/(3 - - 5) = 4/8 = 1/2
point slope form=
y-3 = 1/2(x -3)
i assume standard form is y = mx +b
y = 1/2 x +1.5

Answer 5

x1=-5 y1=-1 x2=3 y2=3
slope=(y2-y1)/(x2-x1)=4/8=1/2
y=mx+b, m slope
y=(1/2)x+b
plug in y=3 x=3
3=(1/2)(3)+b
3=3/2+b
b=3/2
y=(1/2)x+3/2 is the equation.

Answer 6

slope = (3--1)/(3--5)=4/8=1/2

(y-3)/(x-3)=1/2
2(y-3)=(x-3)
2y-x=3

Answer 7

y = 0.5x + 1.5